Login to BatWeb
Forgot your password?
BatMUD Forums > Bs > Re: Earth's mass and jump day.
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
-Metsän Pöllö
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
-Metsän Pöllö
Rating:
2
Votes:
2
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
Diego wrote:
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
Anyway.
Jumping up causes an impulse force in two directions. One, pushing the surface
you are standing on down, and one pushing you up. This will result in a small
force pushing the earth in some direction, while you will get a certain amount
of kinetic energy the other way. What happens next? The gravitational force
will pull you back down again. "Jolly good" you think. Now we get the same
energy applied in the same direction _twice_, because the landing is identical
to the takeoff force-wise. Sadly nobody thought about what happens when the
earth attracts you back. You "push" the earth as much with takeoff+landing as
you attract the earth gravitationally while in the air. Yes, YOU attract the
earth too. Even you mudders.
So, energy is transformed from adeninetriphosphate to heat in your muscles at
takeoff, some heat+sonic effects in the landing, but NO energy goes into
pushing earth into another orbit. Sorry.
Rating:
3
Votes:
5
It would be easier to understand if you think gravitation as being tied to the
earth with a rubber band. Jumping up will flex the rubber band and 'pull' at
its mount point as much as it pulls you down.
earth with a rubber band. Jumping up will flex the rubber band and 'pull' at
its mount point as much as it pulls you down.
Rating:
3
Votes:
3
Malar wrote:
Diego wrote:
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
Anyway.
Jumping up causes an impulse force in two directions. One, pushing the surface
you are standing on down, and one pushing you up. This will result in a small
force pushing the earth in some direction, while you will get a certain amount
of kinetic energy the other way. What happens next? The gravitational force
will pull you back down again. "Jolly good" you think. Now we get the same
energy applied in the same direction _twice_, because the landing is identical
to the takeoff force-wise. Sadly nobody thought about what happens when the
earth attracts you back. You "push" the earth as much with takeoff+landing as
you attract the earth gravitationally while in the air. Yes, YOU attract the
earth too. Even you mudders.
So, energy is transformed from adeninetriphosphate to heat in your muscles at
takeoff, some heat+sonic effects in the landing, but NO energy goes into
pushing earth into another orbit. Sorry.
This signature is intentionally left blank.
Rating:
1
Votes:
1
Zulle wrote:
Malar wrote:
Diego wrote:
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
Anyway.
Jumping up causes an impulse force in two directions. One, pushing the surface
you are standing on down, and one pushing you up. This will result in a small
force pushing the earth in some direction, while you will get a certain amount
of kinetic energy the other way. What happens next? The gravitational force
will pull you back down again. "Jolly good" you think. Now we get the same
energy applied in the same direction _twice_, because the landing is identical
to the takeoff force-wise. Sadly nobody thought about what happens when the
earth attracts you back. You "push" the earth as much with takeoff+landing as
you attract the earth gravitationally while in the air. Yes, YOU attract the
earth too. Even you mudders.
So, energy is transformed from adeninetriphosphate to heat in your muscles at
takeoff, some heat+sonic effects in the landing, but NO energy goes into
pushing earth into another orbit. Sorry.
it's orbit making it crash into the sun. Now if we're so eager to become
extinct by polluting and such why not just make it more interesting. Hope to
see you jumping.
Rating:
2
Votes:
2
Malar wrote:
Diego wrote:
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
Anyway.
Jumping up causes an impulse force in two directions. One, pushing the surface
you are standing on down, and one pushing you up. This will result in a small
force pushing the earth in some direction, while you will get a certain amount
of kinetic energy the other way. What happens next? The gravitational force
will pull you back down again. "Jolly good" you think. Now we get the same
energy applied in the same direction _twice_, because the landing is identical
to the takeoff force-wise. Sadly nobody thought about what happens when the
earth attracts you back. You "push" the earth as much with takeoff+landing as
you attract the earth gravitationally while in the air. Yes, YOU attract the
earth too. Even you mudders.
So, energy is transformed from adeninetriphosphate to heat in your muscles at
takeoff, some heat+sonic effects in the landing, but NO energy goes into
pushing earth into another orbit. Sorry.
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
all that mass landing at once. YOU ARE MORON JUMP DAY WILL WORK
- blackstar -
Rating:
-11
Votes:
16
Blackstar wrote:
Vince wrote:
Did a quickie calculation, if earth's mass would be 6*10^24 (got it off the
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
net) and taking a hypothetical figure that the mean weight of all the people
on earth would be 80kg (the american fatsos and the over billion starving 3rd
worlders balance each other out) I got something like this...
(6*10^12 * 80) / (6 * 10^24) = 8 * 10^-14.
Now if I'm correct about this, the effect of jump day would be about the same
that a 1kg rock would have on a 100 million ton object.
all that mass landing at once. YOU ARE MORON JUMP DAY WILL WORK
surface promptly. Energy toward changing earth trajectory ~= 0.
If I had all the money I'd spent on drink, I'd spend it on drink.
-- Sir Henry Rawlinson
© 1990-2024 Balanced Alternative Techniques ry. All rights reserved. BatMUD™ is a registered trademark of Balanced Alternative Techniques ry.
The individual comments are the property of their posters, and may not reflect the views or opinions of the administration.