Shinarae wrote:
The solution to the puzzle:
The only way that this repeated division can possibly work is if the number in
question is large enough to be divided by four, five times, and get whole
numbers each time. 4^5 is 1,024 but of course you can't use that because that
goes in evenly. The closest nearby numbers that have one left over when you
divide by 4 are 1,025 and 1,021. However, if you use 1,025 then the remaining
1,024 (after the newbie's cut) gives a multiple of four when completed, so
that doesn't work. 1,021 on the other hand wors perfectly. So does 1,021 plus
any multiple of 1,024. Using 1,021:
-- the tank gets 255, the newbie gets 1, and the safe has the last 765
-- the mage gets 191, the newbie gets 1, and the safe has the last 573
-- the healer gets 143, the newbie gets 1, and the safe has the last 429
-- the bard gets 107, the newbie gets 1, and the safe has the last 321
-- at the end, they each get 80 and the newbie gets 1.
Total: tank gets 335, mage gets 271, healer gets 223, bard gets 187, and newbi
gets 5. Total = 1,021
Shinarae Lluminus
I think Shinarae's answer is wrong. What type of lame-ass party can't carry